Transistors $$Q_{1}$$ and $$Q_{2}$$ are identical and $$\beta >> 1$$ in the circuit shown in the figure below. The output voltage is $$(V_t = 0.026 V)$$:

A

$$2 \log_{10}(\frac{v_{2}}{v_{1}} \frac{R_{1}}{R_{2}})$$

B

$$\log_{10}(\frac{v_{2}}{v_{1}} \frac{R_{1}}{R_{2}})$$

C

$$2.3 \log_{10}(\frac{v_{2}}{v_{1}} \frac{R_{1}}{R_{2}})$$

D

$$4.6 \log_{10}(\frac{v_{2}}{v_{1}} \frac{R_{1}}{R_{2}})$$