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A tube of negligible mass and uniform cross section filled with a liquid of mass $$20\text{ g}$$ is floating in water as shown. When a lead shot is dropped in to the tube, the length of the submerged portion increases by $$L$$. The buoyant force on the tube after the lead shot is dropped is (Assume acceleration due to gravity $$= 10\text{ ms}^{-2}$$)
[image]
Initially the submerged length is $$2L$$ (from the figure) and the buoyant force equals the weight, $$0.02 \times 10 = 0.2\text{ N}$$. For a tube of uniform cross section the buoyant force is proportional to the submerged length. After the shot the submerged length is $$3L$$, so the buoyant force is $$\frac{3}{2} \times 0.2 = 0.3\text{ N}$$.
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