Which two signs need to be interchanged to make the given equation correct?
$$6\div 3 + 12 \times 4 - 9 = 12$$

Given Equation : $$6\div 3 + 12 \times 4 - 9 = 12$$

We will check option wise and Solve it as per the rule of BODMAS :

Option A : $$-, \times$$

Changed Equation : $$6\div3+12-4\times\ 9=12$$

$$2+12-4\times\ 9=12$$

$$2+12-36=12$$

$$22\ne\ 12$$

Option A is incorrect.

Option B : $$\div, \times$$

Changed Equation : $$6\times\ 3+12\div4-9=12$$

$$6\times\ 3+3-9=12$$

$$18+3-9=12$$

$$12=12$$

Option B is correct.

Option C : $$-, +$$

Changed Equation : $$6\div3-12\times4+9=12$$

$$2-12\times4+9=12$$

$$2-48+9=12$$

$$-37\ne\ 12$$

Option D : $$+, \div$$

Changed Equation :$$6+3\div12\times4-9=12$$

$$6+\frac{3}{12}\times4-9=12$$

$$6+1-9=12$$

$$-2\ne\ 12$$

Option D is incorrect.

Hence, Option B is correct.