Which two numbers need to be interchanged to make the given equation correct?
$$12\div 3 - 6 + 4 \times 96 = 74$$

Given Equation : $$12\div 3 - 6 + 4 \times 96 = 74$$

 We have to check it option wise and As per the rule of BODMAS :

Option A : 6, 4 

Changed Equation : $$12\div3-4+6\times96=74$$

$$4-4+6\times96=74$$

$$4-4+576=74$$

$$576\ne\ 74$$

Option A is incorrect. 

Option B : 12, 96

Changed Equation : $$96\div3-6+4\times12=74$$

$$32-6+4\times12=74$$

$$32-6+48=74$$

$$74=74$$

Hence, Option B is correct. 

Option C : 3, 6

Changed Equation : $$12\div6-3+4\times96=74$$

$$2-3+4\times96=74$$

$$2-3+384=74$$

$$383\ne\ 74$$

Option C is incorrect.