Solution
Given : $$a^2 + b^2 = 25$$ ----------(i)
Also, $$a-b=3$$
Squaring both sides, we get :
=> $$(a-b)^2=(3)^2$$
=> $$a^2+b^2-2ab=9$$
=> $$25-2ab=9$$ [Using (i)]
=> $$2ab=25-9=16$$
=> $$ab=\frac{16}{2}=8$$
=> Ans - (B)
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