Question 42

A hollow cylinder of thickness 0.7 cm and height 15 cm is made of iron. If inner radius of cylinder is 3.5 cm, then what is the total surface area (in cm$$^2$$) of the hollow cylinder?

inner radius,$$r_2=3.5\ cm.$$ and outer radius, $$r_1=\left(0.7+3.5\ \right)cm=4.2\ cm.$$

$$Later\ surface\ \ area\ =\ 2\pi h\left(r_1+r_2\right).$$

Total surface area = $$2\pi h\left(r_1+r_2\right)+2\pi\left(r_1^2-r_2^2\right).$$

                            = $$2\times\frac{22}{7}15\left(3.5+4.2\right)+2\times\frac{22}{7}\left(4.2^2-3.5^2\right).$$

                            = $$726+33.88$$

                            = 759.88 cm.

C is correct choice.

Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

MAT Quant Questions | MAT Quantitative Ability

MAT DILR Questions | LRDI Questions For MAT

MAT Verbal Ability Questions | VARC Questions For MAT