Sign in
Please select an account to continue using cracku.in
↓ →
The least value of $$\alpha \in R$$ for which $$4 \alpha x^2 + \frac{1}{x} \geq 1$$, for all x > 0, is
$$\frac{1}{64}$$
$$\frac{1}{32}$$
$$\frac{1}{27}$$
$$\frac{1}{25}$$
Create a FREE account and get:
Terms of Service
CAT Formulas PDF CAT Exam Syllabus PDF CAT Study Plan PDF Cracku Brochure