A computer producing factory has only two plants $$T_1$$ and $$T_2$$ Plant $$T_1$$ produces 20% and plant $$T_2$$ produces 80% of the total computers produced. 7% of computers produced in the factory turn out to be defective. It is known that P (computer turns out to be defective given that it is produced in plant $$T_1$$) = 10P (computer turns out to be defective given that it is produced in plant $$T_2$$), where P(E) denotes the probability of an event E. A computer produced in the factory is randomly selected and it does not turn out to be defective. Then the probability that it is producedin plant $$T_2$$ is