Question 41
Divide 3740 in three parts in such a way that half of the first part, one-third of the second part and one-sixth of the third part are equal.
Solution
Let the three parts be a , b and c.
$$\frac{a}{2} = \frac{b}{3} =\frac{c}{6}$$ = k
a = 2k
b = 3k
c = 6k
a + b + c =3740
2k + 3k + 6k = 3740 => k =340
a = 680 , b =1020 , c=2040
So, the answer would be option c)680, 1020, 2040
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