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Question 40

The pulley shown in the figure is made using a thin rim and two rods of length equal to the diameter of the rim. The rim and each rod have a mass of M. Two blocks of mass of M and m are attached to two ends of a light string passing over the pulley, which is hinged to rotate freely in vertical plane about its center. The magnitudes of the acceleration experienced by the blocks is ___________
(assume no slipping of string on pulley).

40 slot 2

The pulley consists of a thin rim and two rods (length $$L = 2R$$).

Rim: $$I_{rim} = MR^2$$

Two Rods (about center): $$I_{rods} = 2 \times \left( \frac{1}{12} M L^2 \right) = 2 \times \left( \frac{1}{12} M (2R)^2 \right) = \frac{2}{3} MR^2$$

Total $$I$$: $$I = MR^2 + \frac{2}{3} MR^2 = \frac{5}{3} MR^2$$

Equations:

Force on $$M$$: $$Mg - T_2 = Ma$$

Force on $$m$$: $$T_1 - mg = ma$$

Torque on Pulley: $$(T_2 - T_1)R = I\alpha \implies T_2 - T_1 = \frac{I a}{R^2}$$

$$(Mg - Ma) - (mg + ma) = \frac{\frac{5}{3} MR^2 \cdot a}{R^2}$$

$$(M - m)g - (M + m)a = \frac{5}{3} Ma$$

$$(M - m)g = \left( M + m + \frac{5}{3} M \right) a$$

$$(M - m)g = \left( \frac{8}{3} M + m \right) a$$

$$a = \frac{(M - m)g}{\frac{8}{3} M + m}$$

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