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$$X$$ is a $$5$$ digit number. Let $$Y$$ be the sum of the digits of $$X$$. Let $$Z$$ be the sum of the digits of $$Y$$. Then the maximum possible value that $$Z$$ can have is
The largest possible digit sum of a five digit number is $$45$$. Among the integers from $$1$$ to $$45$$, the largest digit sum is obtained at $$39$$, whose digit sum is $$3+9=12$$. Hence the maximum possible value of $$Z$$ is $$12$$.
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