Question 4

If $$x < y$$ and $$x + y = k$$ then

Solution

$$\frac{k}{2} = \frac{x + y}{2}$$ is the average of $$x$$ and $$y$$, which always lies between them. So $$x < \frac{k}{2} < y$$ for every value of $$k$$, positive, negative or zero. Hence options c and d are correct, and a, b and e are false.

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