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Question 4

An average force of 125 N is applied on a machine gun firing bullets each of mass 10 g at the speed of 250 m s$$^{-1}$$ to keep it in position. The number of bullets fired per second by the machine gun is:

Solution

Average force exerted by a machine gun equals the rate of change of momentum of the fired bullets.

$$F = n \cdot m \cdot v$$

$$125 = n \cdot (10 \times 10^{-3}) \cdot 250$$

$$125 = n \cdot 2.5 \implies n = \frac{125}{2.5} = 50$$

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