8 men and 4 women together can complete a piece of work in 6 days. The work done by a man in one day is double the work done by a woman in one day. If 8 men and 4 women started working and after 2 days 4 men left and 4 new women joined, in how many more days will the work be completed?

Let the work done by a woman in one day = x units

The work done  by a man in one day = 2x units

8 men and 4 women together can complete a piece of work in 6 days.

Total work = (8*2x+4*x)6 = 120x units

Amount of work done by 8 men and 4 women in 2 days = (8*2x+ 4*x)2 = 40x units

The remaining 80x units will be done by 8 women and 4 men

Number of days taken by 8 women to complete 80x units of work = $$\ \frac{\ 80x}{16x}$$

=5 days

A is the correct answer.