Question 39

What is the sum of the first 12 terms of an arithmetic progression if the first term is -19 and last term is 36?

Solution

First term of AP = $$a=-19$$ and last term = $$l=36$$

Number of terms = $$n=12$$

Sum of AP = $$\frac{n}{2}(a+l)$$

= $$\frac{12}{2}(-19+36)$$

= $$17 \times 6=102$$

=> Ans - (C)

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