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What is the lateral shift of a ray refracted through a parallel-sided glass slab of thickness 'h' in terms of the angle of incidence 'i' and angle of refraction 'r', if the glass slab is placed in air medium?
$$\cos r = \frac{h}{L} \implies L = \frac{h}{\cos r}$$
$$\sin(i - r) = \frac{d}{L} \implies d = L \sin(i - r)$$
$$d = \frac{h \sin(i - r)}{\cos r}$$
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