Question 38

The product "A" and "B" formed in below reactions are:

Solution

First reaction proceeds via $$E_1$$ reaction allowing for carbocation rearrangement. Second reaction proceeds via $$E_2$$ due to a bulky base and thus no carbocation is formed.

Reaction 1: E1 Elimination $$\rightarrow$$ Zaitsev Product (Most stable/substituted alkene).

Reaction 2: E2 Elimination $$\rightarrow$$ Hofmann Product (Least substituted alkene due to bulky base).

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The product "A" and "B" formed in below reactions are:

Solution

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