Question 38

Meghnad can do a piece of work in 45 hours. If he is joined by Jayshri, who is 50% more efficient, in what time will they together finish the work?

Solution

Let total work to be done = 90 units

Meghnad's efficiency = $$\frac{90}{45} = 2$$ units/hr

Jayshri is 50% more efficient than Meghnad, => Jayshri's efficiency = $$\frac{150}{100} \times 2 = 3$$ units/hr

=> Meghnad and Jayshri 1 day's work = 2 + 3 = 5 units/hr

$$\therefore$$ Time taken by them to finish the work together = $$\frac{90}{5} = 18$$ hours

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