Question 38
Find the length of a chord which is at a distance of 8 cm from the centre of a circle having a radius of 17 cm.
Solution
The perpendicular distance of the chord from center O is OA i.e. 8cm and radius is OB i.e. 17cm.
AB i.e. half of the length of the chord = $$\sqrt{\ OB^2-OA^2}$$
==> $$\sqrt{\ 17^2-8^2}=15$$ cm.
Length of the chord = 2*15 = 30 cm.
