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Find the length of a chord which is at a distance of 8 cm from the centre of a circle having a radius of 17 cm.
The perpendicular distance of the chord from center O is OA i.e. 8cm and radius is OB i.e. 17cm.
AB i.e. half of the length of the chord =Β $$\sqrt{\ OB^2-OA^2}$$
==>Β $$\sqrt{\ 17^2-8^2}=15$$ cm.
Length of the chord = 2*15 = 30 cm.
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