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P and Q are isomers of dicarboxylic acid $$C_{4}H_{4}O_{4}$$. Both decolorize $$\frac{Br}{H_{2}O}$$. On heating, P forms the cyclic anhydride.
Upon treatment with dilute alkaline $$KMnO_{4}$$, P as well as Q could produce one or more than one from S, T and U.
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