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The value of $$lim_{x \rightarrow 0} \frac{\sin(x^2)}{x \sin x}$$ is
0
1
2
$$\infty$$
We know that $$lim_{x \rightarrow 0} \frac{\sin x}{x}$$ is 1
=$$\lim_{x\rightarrow\ 0} \frac{sin x^2}{x^2}*\frac{x}{sin x}$$
= 1
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