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Tangents are drawn from the point P(3, 4) to the ellipse $$\frac{x^2}{9} + \frac{y^2}{4} = 1$$ touching the ellipse at point A and B.
The orthocenter of the triangle PAB is
$$\left(5, \frac{8}{7}\right)$$
$$\left(\frac{7}{5}, \frac{25}{8}\right)$$
$$\left(\frac{11}{5}, \frac{8}{5}\right)$$
$$\left(\frac{8}{25}, \frac{7}{5}\right)$$
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