Question 34
In a triangle PQR, the side QR is extended to S. ∠QPR = 72° and ∠PRS = 110°, then the value of ∠PQR is:
Solution
Given : ∠QPR = 72° and ∠PRS = 110°
To find : ∠PQR = $$\theta$$ = ?
Solution : Using exterior angle property
=> ∠P + ∠Q = ∠PRS
=> $$72^\circ+\theta=110^\circ$$
=> $$\theta=110-72=38^\circ$$
=> Ans - (A)
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