Consider the oxides of group 14 elements $$SiO_2, GeO_2, SnO_2, PbO_2, CO$$ and $$GeO$$. The amphoteric oxides are

As we move down Group 14 from carbon to lead, metallic character increases. Consequently, the nature of the oxides changes from acidic to amphoteric.

$$SiO_2$$ and $$GeO_2$$ are acidic oxides. $$GeO$$ also exhibits acidic character.

$$CO$$ is a neutral oxide and neither shows acidic nor basic behavior.

$$SnO_2$$ and $$PbO_2$$ are amphoteric oxides. They react with both acids and bases, exhibiting both acidic and basic properties.

Therefore, the pairs containing $$GeO$$ and $$GeO_2$$ or $$SiO_2$$ and $$GeO_2$$ cannot be correct because these oxides are acidic.

The pair containing $$SnO_2$$ and $$CO$$ cannot be correct because $$SnO_2$$ is amphoteric whereas $$CO$$ is neutral.

The only pair in which both oxides are amphoteric is

$$SnO_2 \text{ and } PbO_2$$

Hence, the correct answer is

$$SnO_2 \text{ and } PbO_2$$