Match List I with List II:

Choose the correct answer from the options given below:

We need to match each element in List-I with its correct ground-state electronic configuration in List-II.

Matching Analysis:

• (A) Nitrogen ($$\text{N}$$): Atomic number 7. Its valence configuration is $$2s^2 2p^3$$.
  $$\implies \text{(A)} \rightarrow \text{(III)}$$
• (B) Sulfur ($$\text{S}$$): Atomic number 16. Its valence configuration is $$3s^2 3p^4$$.
  $$\implies \text{(B)} \rightarrow \text{(II)}$$
• (C) Bromine ($$\text{Br}$$): Atomic number 35. Its valence configuration is $$3d^{10} 4s^2 4p^5$$.
  $$\implies \text{(C)} \rightarrow \text{(I)}$$
• (D) Krypton ($$\text{Kr}$$): Atomic number 36. Its valence configuration is $$3d^{10} 4s^2 4p^6$$.
  $$\implies \text{(D)} \rightarrow \text{(IV)}$$