Keeping tl1e significant figures in view, the sum of the physical quantities 52.01 m, 153.2 m and 0.123 m is:

Adding 52.01 m + 153.2 m + 0.123 m with significant figures.

In addition, the result should have the same number of decimal places as the quantity with the least decimal places.

52.01 has 2 decimal places, 153.2 has 1 decimal place, 0.123 has 3 decimal places.

Least decimal places = 1 (from 153.2).

Sum = 52.01 + 153.2 + 0.123 = 205.333

Rounded to 1 decimal place: 205.3 m.

The answer is Option 4: 205.3 m.