Question 33

$$2IO_3^- + xI^- + 12H^+ \rightarrow 6I_2 + 6H_2$$ What is the value of x?

Name: 2IO_3^- + xI^- + 12H^+ \\rightarrow 6I_2 + 6H_2 What is the value of x?
Uploaded: 2026-06-21T17:27:58.326109+05:30
Duration: 1 min 41 s
Description: 2IO_3^- + xI^- + 12H^+ \\rightarrow 6I_2 + 6H_2 What is the value of x?

Solution

Total 12 mole of $$I$$ in RHS side of the reaction.

$$2 + x = 12$$

$$x = 12 - 2$$

$$x = 10$$

Hence on the left hand side to balance it x must be 10.

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$$2IO_3^- + xI^- + 12H^+ \rightarrow 6I_2 + 6H_2$$ What is the value of x?

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