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Question 33

$$2IO_3^- + xI^- + 12H^+ \rightarrow 6I_2 + 6H_2$$ What is the value of x?

Solution

Total 12 mole of $$I$$ in RHS side of the reaction.

$$2 + x = 12$$

$$x = 12 - 2$$

$$x = 10$$

Hence on the left hand side to balance it x must be 10.

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