In the following circuit, $$R_1 = 6\,\Omega$$, $$R_2 = 12\,\Omega$$, $$V = 16\,\mathrm{V}$$. The currents $$I_1$$ and $$I_2$$ flow through the resistances $$R_1$$ and $$R_2$$ respectively.

A

power generated across $$R_1$$ is 42.6 watt

B

the ratio of $$\frac{I_1}{I_2} = 2$$

C

total current drawn from the cell is 4 ampere

D

as $$R_2 = 2R_1$$, the voltage across $$R_2$$ will be twice the voltage across $$R_1$$