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Each question is provided with 4-alternative answers. One or more than one of them are correct answers. Indicate the correct answer by A,B,C,D.
$$80\%$$ of a first order chemical reaction completed in 100 sec, what time it will take for the completion of $$99.2\%$$
For a first order reaction the fraction remaining is $$e^{-kt}$$. After 100 s, $$\frac{1}{5}$$ remains. At $$99.2\%$$ completion, $$0.008 = \frac{1}{125} = \left(\frac{1}{5}\right)^3$$ remains, which takes three such intervals, i.e. $$300$$ s.
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