Question 31

Which of the following is the correct set of quantum numbers for differentiating electron between calcium and scandium

Solution

Calcium is $$[\text{Ar}]4s^2$$ and scandium is $$[\text{Ar}]3d^1 4s^2$$, so the differentiating electron enters a $$3d$$ orbital. That gives $$n = 3$$, $$l = 2$$, and as the first $$d$$ electron $$m = -2$$ with $$s = +\frac{1}{2}$$.

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