Question 31

Find $$2 \circledast 3$$, where $$2\circledast 3$$ need not be equal to $$3\circledast2$$

I. $$1 \circledast 2$$=3

II. $$a \circledast b=\frac{a+b}{a}$$, where a and b are positive.

Solution

The definition of the given function is expressed in statement 2, where $$a \circledast b=\frac{a+b}{a}$$

Hence $$2\circledast3=\frac{2+3}{2}$$.

Hence the answer can be determined by b alone. A does not give any releant information.

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