A thief is stopped by a policeman from a distance of 500 metres. When the policeman starts the chase, the thief also starts running. Assuming the speed of the thief as 10 km/h and that of police man as 18 km/h, how far the thief would have run, before he is over­-taken?

Since the thief is escaping from the police man, thus they both are running in same direction.

Speed of thief = 10 km/hr and speed of policeman = 18 km/hr

=> Relative speed = 18 - 10 = 8 km/hr

Distance between them = 500 metres = 0.5 km

=> Time taken = $$\frac{distance}{speed}$$

= $$\frac{0.5}{8} = \frac{1}{16}$$ hr

$$\therefore$$ Distance covered by thief before he was caught = $$10 \times \frac{1}{16}$$

= 0.625 km = 625 metres

=> Ans - (A)