Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
The first I.P values of three elements are 1314, 1680, 2080 $$\text{kJ mol}^{-1}$$. The correct sequence of elements is
Across period 2 the first ionization enthalpy increases from O to F to Ne, and O is lower than expected because its paired $$2p$$ electron is easier to remove. So 1314, 1680 and 2080 belong to O, F and Ne respectively.
Was this solution helpful?
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation