Question 30

The first I.P values of three elements are 1314, 1680, 2080 $$\text{kJ mol}^{-1}$$. The correct sequence of elements is

Solution

Across period 2 the first ionization enthalpy increases from O to F to Ne, and O is lower than expected because its paired $$2p$$ electron is easier to remove. So 1314, 1680 and 2080 belong to O, F and Ne respectively.

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