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The correct set of quantum numbers for the valence electron of sodium (Z = 11) is
Sodium is $$1s^2 2s^2 2p^6 3s^1$$, so its valence electron is in the $$3s$$ orbital. That gives $$n = 3$$, $$l = 0$$, $$m = 0$$ and $$s = +\frac{1}{2}$$.
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