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Option A: $$C = \overline{\bar{A} + (A \cdot B)} = A \cdot \overline{(A \cdot B)} = A \cdot (\bar{A} + \bar{B}) = A\bar{B}$$
Option B: $$C = (A + B) \cdot B = AB + B = B$$
Option C: $$C = (A \cdot B) + \bar{B} = A + \bar{B}$$
Option D: $$C = \overline{A \cdot B} = \bar{A} + \bar{B}$$
The circuit that correctly represents the truth table is Option A .
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