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If there were 9-periods in the periodic table then how many elements would $$9^{\text{th}}$$ period can maximum comprise of
By the $$(n + l)$$ filling order, the 9th period would fill $$9s$$, $$6g$$, $$7f$$, $$8d$$ and $$9p$$. These hold $$2 + 18 + 14 + 10 + 6 = 50$$ electrons, so the 9th period could have at most 50 elements.
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