Question 29

If $$\mid \frac{x + 1}{x - 1} \mid > \frac{x + 1}{x - 1}$$, then

Solution

$$\mid \frac{x + 1}{x - 1} \mid will be greater than \frac{x + 1}{x - 1}$$ only if $$\frac{x + 1}{x - 1}$$ < 0

$$\therefore$$ x $$\in$$ (-1,1)

Hence B is the correct answer.

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