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If $$\mid \frac{x + 1}{x - 1} \mid > \frac{x + 1}{x - 1}$$, then
$$-1 \leq x \leq -1$$
$$-1 < x < 1$$
$$x > 1$$
$$x < -1$$
$$\mid \frac{x + 1}{x - 1} \mid will be greater than \frac{x + 1}{x - 1}$$ only if $$\frac{x + 1}{x - 1}$$ < 0
$$\therefore$$ x $$\in$$ (-1,1)
Hence B is the correct answer.
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