Question 29

If 7 (110) 4 and 19 (930), 12, then what is the value of ‘A’ in 16 (A) 9 ?

Solution

The pattern followed is that for the numbers : $$x(z)y$$, $$z=(x+y)\times(x+y-1)$$

Eg :- 7 (110) 4 => Here $$7+4=11\equiv(11\times10)=110$$

and 19 (930) 12 => Here $$19+12=31\equiv(31\times30)=930$$

Similarly, 16 (A) 9 => Here $$16+9=25$$

=> $$A=25\times24=600$$

=> Ans - (B)

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