Question 29

A large watermelon weighs $$20$$ kg with $$98\%$$ of its weight being water. It is left outside in the sunshine for some time. Some water evaporated and the water content in the watermelon is now $$95\%$$ of its weight in water. The reduced weight in kg is ------.

Correct Answer: 12

The pulp (non-water) content is $$2\%$$ of $$20$$ kg, i.e. $$0.4$$ kg, and this stays constant.

After evaporation, the solid content is $$5\%$$ of the new weight.

$$\dfrac{5}{100} w = 0.4$$kg

So, the new weight is

$$\dfrac{0.4}{0.05}=8$$ kg.

The weight reduction is $$20-8=12$$ kg.

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