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The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between t = 0 to t = 4 s ?
$$\text{Distance} = \text{Area of triangle (0 to 2 s)} + \text{Area of rectangle (2 to 4 s)}$$
$$\text{Distance} = \left(\frac{1}{2} \times 2 \times 10\right) + (2 \times 10) = 10 + 20 = 30\text{ m}$$
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