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The sum of the number of lone pairs of electrons on each central atom in the following species is
$$\left[TeBr_6 \right]^{2−}, \left[BrF_2 \right]^+, SNF_3$$, and $$\left[XeF_3 \right]^−$$
(Atomic numbers: N = 7, F = 9, S = 16, Br = 35, Te = 52, Xe = 54)
Correct Answer: 6
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