For $$0 < \theta < \frac{\pi}{2}$$, the solution(s) of
$$ \sum_{m=1}^{6}\cosec\left(\theta + \frac{(m - 1)\pi}{4}\right)\cosec\left(\theta + \frac{m\pi}{4}\right) = 4\sqrt{2}$$
is(are)

A

$$\frac{\pi}{4}$$

B

$$\frac{\pi}{6}$$

C

$$\frac{\pi}{12}$$

D

$$\frac{5 \pi}{12}$$