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A conducting circular loop is placed in a uniform magnetic field of $$0.4$$ T with its plane perpendicular to the field. Somehow, the radius of the loop starts expanding at a constant rate of $$1$$ mm s$$^{-1}$$. The magnitude of induced emf in the loop at an instant when the radius of the loop is $$2$$ cm will be _____ $$\mu$$V.
Correct Answer: 50
$$\phi = BA = B(\pi r^2)$$
$$e = \left|\frac{d\phi}{dt}\right| = \frac{d}{dt}(B\pi r^2) = 2\pi B r \frac{dr}{dt}$$
$$e = 2\pi(0.4)(0.02)(10^{-3}) = 16\pi \times 10^{-6}\text{ V} = 16\left(\frac{22}{7}\right)\,\mu\text{V} \approx 50.28\,\mu\text{V}$$
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