In the adjoining figure, the value of $$x$$ in degrees is

At $$B$$, the line through the upper intersection makes an angle of $$108^\circ$$ with the rightward horizontal line. At the upper intersection, the angle between this line and the line through $$A$$ is $$60^\circ$$. Therefore, the latter line makes $$108^\circ-60^\circ=48^\circ$$ with the horizontal, so $$x=48^\circ$$.