If $$\sin 60^\circ + \cos 45^\circ = x$$, then the value of $$x$$ is
Expression : sin 60° + cos 45° = x
= $$\frac{\sqrt{3}}{2} + \frac{1}{\sqrt{2}}$$
= $$\frac{\sqrt{3}}{2} + \frac{\sqrt{2}}{2}$$
= $$\frac{\sqrt{3} + \sqrt{2}}{2}$$
=> Ans - (B)
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