Question 26
If $$f(t) = t^{2}$$, compute f(99) and f(101), Between those times, what is the increase in f divided by the increase in t?
Solution
f(99) = $$99^2$$ and f(101) = $$101^2$$.
Increase in value of f = $$101^2\ -99^2$$ = (101 - 99)(101 + 99) = 2*200 = 400,
and increase in value of t = 101 - 99 = 2.
Required answer is : $$\frac{400}{2}=200$$.
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