Question 26

A stream of particles each of mass 1 g moving horizontally with a velocity of $$5\text{ m/s}$$ strike a vertical wall. The particles stick to the wall after hitting the wall. Number of particles per $$\text{m}^3$$ of the stream is 10000.<br>The change in momentum (in $$\text{kg m s}^{-1}$$) of the particles that strike an area $$2\text{ m}^2$$ of the wall in four seconds.


Correct Answer: 2000

Solution

The number of particles striking $$2\text{ m}^2$$ in 4 s is $$10000 \times 2 \times 5 \times 4 = 400000$$. Each particle of mass $$0.001\text{ kg}$$ stops, losing momentum $$0.001 \times 5 = 0.005\text{ kg m s}^{-1}$$. The total change in momentum is $$400000 \times 0.005 = 2000\text{ kg m s}^{-1}$$.

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