The batting average for 40 innings of a cricketer is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded, the average of the remaining 38 innings is 48 runs. The highest score of the player is

total runs scored by the player in 40 innings = $$ 40 \times 50 = 2000 $$

total runs scored by the player in 38 innings after excluding 2 innings = $$ 38 \times 48 = 1824 $$

sum of the scores of the excluded innings = 2000 - 1824 = 176

given that scores of the excluded innings differ by 172

hence lets take the highest score as x+172 and lowest score as x

now x+x+172 = 176

2x = 4

x = 2

highest score = 172+2 = 174