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An ellipse intersects the hyperbola $$2x^2 - 2y^2 = 1$$ orthogonally. The eccentricity of the ellipse is reciprocal of that of the hyperbola. If the axes of the ellipse are along thecoordinate axes, then
Equation of ellipse is $$x^2 + 2y^2 = 2$$
The foci of ellipse are $$(\pm 1, 0)$$
Equation of ellipse is $$x^2 + 2y^2 = 4$$
The foci of ellipse are $$(\pm \sqrt{2}, 0)$$
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