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If $$I_n = \int_{-\pi}^{\pi}\frac{\sin nx}{(1 + \pi^x) \sin x}dx$$, n = 0, 1, 2, 3, ....,then
$$I_n = I_{n+2}$$
$$\sum_{m=1}^{10}I_{2m+1} = 10 \pi$$
$$\sum_{m=1}^{10}I_{2m} = 0 \pi$$
$$I_n = I_{n+1}$$
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